5-6[2t-2(t-3)]=8-t

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Solution for 5-6[2t-2(t-3)]=8-t equation:


Simplifying
5 + -6[2t + -2(t + -3)] = 8 + -1t

Reorder the terms:
5 + -6[2t + -2(-3 + t)] = 8 + -1t
5 + -6[2t + (-3 * -2 + t * -2)] = 8 + -1t
5 + -6[2t + (6 + -2t)] = 8 + -1t

Reorder the terms:
5 + -6[6 + 2t + -2t] = 8 + -1t

Combine like terms: 2t + -2t = 0
5 + -6[6 + 0] = 8 + -1t
5 + -6[6] = 8 + -1t

Multiply -6 * 6
5 + -36 = 8 + -1t

Combine like terms: 5 + -36 = -31
-31 = 8 + -1t

Solving
-31 = 8 + -1t

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add 't' to each side of the equation.
-31 + t = 8 + -1t + t

Combine like terms: -1t + t = 0
-31 + t = 8 + 0
-31 + t = 8

Add '31' to each side of the equation.
-31 + 31 + t = 8 + 31

Combine like terms: -31 + 31 = 0
0 + t = 8 + 31
t = 8 + 31

Combine like terms: 8 + 31 = 39
t = 39

Simplifying
t = 39

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